-10v^2-2=-9v

Solution for -10v^2-2=-9v equation:

-10v^2-2=-9v

We move all terms to the left:

-10v^2-2-(-9v)=0

We get rid of parentheses

-10v^2+9v-2=0

a = -10; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·(-10)·(-2)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*-10}=\frac{-10}{-20}
=1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*-10}=\frac{-8}{-20}
=2/5
$